Online reinforcement calculator. Quickly calculate the number, length and weight of reinforcing bars for foundations, slabs, columns and walls.
Calculate the required number and weight of reinforcing bars for concrete structures
The online reinforcement calculator will help you calculate the required number and weight of reinforcing bars for concrete structures - slabs, foundations, columns, floors and walls. Specify the dimensions of the structure, the mesh spacing and the diameter of the reinforcement - the tool will instantly calculate the total length, weight and approximate number of rods.
The calculator uses standard formulas for calculating reinforcement in accordance with GOST and building codes. The calculation takes into account the mesh pitch, the diameter of the reinforcing bars, the number of layers of reinforcement and the overlap of the bars when connecting. This allows you to obtain accurate results for the design of reinforcement of any concrete structure.
Let's look at practical examples of calculating the quantity and weight of reinforcement for various structures:
Strip foundation 10×0.5×0.6 m with mesh 200×200 mm
Входные данные:
Length: 10 m
Width: 0.5 m
Height: 0.6 m
Grid pitch: 200 mm (0.2 m)
Reinforcement diameter: 12 mm
Layers: 2Расчёт:
Longitudinal bars: (10/0.2 + 1) × 2 = 51 × 2 = 102 bars
Longitudinal length: 102 × 0.5 = 51 m
Cross bars: (0.5/0.2 + 1) × 2 = 4 × 2 = 8 bars
Cross length: 8 × 10 = 80 m
Total length: 51 + 80 = 131 m
Weight (Ø12): 131 × 0.888 = 116.3 kgРезультат:
131 m of reinforcement, weight 116.3 kg
Тип:
Strip foundation
Two layers for the top and bottom reinforcement chords
Monolithic floor slab with mesh 150×150 mm
Входные данные:
Length: 6 m
Width: 4 m
Height: 0.2 m
Grid pitch: 150 mm (0.15 m)
Reinforcement diameter: 10 mm
Layers: 2Расчёт:
Rods by length: (6/0.15 + 1) × 2 = 41 × 2 = 82 rods
Length by length: 82 × 4 = 328 m
Rods width: (4/0.15 + 1) × 2 = 28 × 2 = 56 rods
Length by width: 56 × 6 = 336 m
Total length: 328 + 336 = 664 m
Weight (Ø10): 664 × 0.617 = 409.7 kgРезультат:
664 m of reinforcement, weight 409.7 kg
Тип:
Floor slab
Two layers provide bending resistance in both directions
Wall 3×2.5×0.3 m with vertical and horizontal reinforcement
Входные данные:
Length: 3 m
Width: 2.5 m
Height: 0.3 m
Grid pitch: 200 mm (0.2 m)
Reinforcement diameter: 8 mm
Layers: 1Расчёт:
Vertical bars: (3/0.2 + 1) = 16 bars
Vertical length: 16 × 2.5 = 40 m
Horizontal bars: (2.5/0.2 + 1) = 14 bars
Horizontal length: 14 × 3 = 42 m
Total length: 40 + 42 = 82 m
Weight (Ø8): 82 × 0.395 = 32.4 kgРезультат:
82 m of reinforcement, weight 32.4 kg
Тип:
Monolithic wall
One layer is sufficient for a thin wall
Square column 3 m high with longitudinal and transverse reinforcement
Входные данные:
Section: 400×400 mm
Height: 3 m
Clamp pitch: 150 mm (0.15 m)
Longitudinal diameter: 16 mm
Clamp diameter: 8 mm
Rods: 4 longitudinalРасчёт:
Longitudinal rods: 4 pcs
Longitudinal length: 4 × 3 = 12 m
Longitudinal weight (Ø16): 12 × 1.58 = 19.0 kg
Number of clamps: (3/0.15 + 1) = 21 clamps
Length of one clamp: 4 × 0.35 = 1.4 m
Clamp length: 21 × 1.4 = 29.4 m
Weight of clamps (Ø8): 29.4 × 0.395 = 11.6 kg
Total weight: 19.0 + 11.6 = 30.6 kgРезультат:
41.4 m of reinforcement, weight 30.6 kg
Тип:
Column
Clamps provide transverse reinforcement
Slab foundation with two-layer mesh 200×200 mm
Входные данные:
Length: 8 m
Width: 8 m
Height: 0.4 m
Grid pitch: 200 mm (0.2 m)
Reinforcement diameter: 14 mm
Layers: 2Расчёт:
Rods by length: (8/0.2 + 1) × 2 = 41 × 2 = 82 rods
Length by length: 82 × 8 = 656 m
Rods width: (8/0.2 + 1) × 2 = 41 × 2 = 82 rods
Length by width: 82 × 8 = 656 m
Total length: 656 + 656 = 1312 m
Weight (Ø14): 1312 × 1.21 = 1587.5 kgРезультат:
1312 m of reinforcement, weight 1587.5 kg
Тип:
Slab foundation
A large area requires a significant amount of reinforcement
Grillage 12×1×0.5 m with mesh 180×180 mm
Входные данные:
Length: 12 m
Width: 1 m
Height: 0.5 m
Grid pitch: 180 mm (0.18 m)
Reinforcement diameter: 12 mm
Layers: 2Расчёт:
Longitudinal bars: (12/0.18 + 1) × 2 = 68 × 2 = 136 bars
Longitudinal length: 136 × 1 = 136 m
Cross bars: (1/0.18 + 1) × 2 = 7 × 2 = 14 bars
Cross length: 14 × 12 = 168 m
Total length: 136 + 168 = 304 m
Weight (Ø12): 304 × 0.888 = 270.0 kgРезультат:
304 m of reinforcement, weight 270.0 kg
Тип:
Grillage
The grillage requires strong reinforcement to distribute the load
The calculator uses standard formulas for calculating reinforcement:
Our reinforcement calculator provides many benefits for accurate reinforcement calculations.
The calculator uses proven formulas in accordance with GOST and building codes, taking into account all parameters: structure dimensions, mesh pitch, reinforcement diameter and number of layers for the most accurate results.
Correct calculation of the amount of reinforcement helps to accurately determine the required material and avoid overspending, which significantly reduces the cost of the project.
Knowing in advance the required quantity and weight of reinforcement, you will be able to properly plan purchases and logistics, avoiding mistakes during construction.
A simple interface and quick calculations allow you to get all the necessary data in a few seconds without complex calculations and formulas.
To properly reinforce concrete structures, it is important to consider many factors that affect strength and durability.
Enter the foundation dimensions (length, width, height), grid spacing and reinforcement diameter. The calculator will calculate the number of rods: for longitudinal (Length/Pitch + 1) × Number of layers, for transverse (Width/Pitch + 1) × Number of layers. Then multiplied by the length of the rods to obtain the total length and mass.
The diameter of the reinforcement for the foundation is selected based on the load and type of foundation. For a strip foundation of a private house, reinforcement Ø10-12 mm is used, for a slab foundation - Ø12-16 mm, for a pile foundation - Ø10-14 mm. For heavy loads, use reinforcement Ø14-16 mm or more.
Yes, the calculator automatically calculates the weight of reinforcement according to GOST depending on the diameter. Reinforcement meter weight: Ø8 mm - 0.395 kg/m, Ø10 mm - 0.617 kg/m, Ø12 mm - 0.888 kg/m, Ø14 mm - 1.21 kg/m, Ø16 mm - 1.58 kg/m, Ø18 mm - 2.0 kg/m, Ø20 mm - 2.47 kg/m.
Mesh spacing is the distance between reinforcing bars in a mesh. For the foundation, the optimal step is 15-25 cm, for floor slabs 10-20 cm, for walls 15-30 cm. A smaller step increases the strength and consumption of reinforcement, a larger step reduces strength. Standard steps: 100, 150, 200, 250, 300 mm.
Yes, the calculator is ideal for calculating strip foundation reinforcement. Select the “foundation” structure type, enter the length, width and height of the foundation, specify the grid spacing and the diameter of the reinforcement. The calculator will calculate the number of longitudinal and transverse rods for the upper and lower chords.
For the floor slab, enter the length and width of the slab, the grid spacing (usually 150-200 mm) and the diameter of the reinforcement (usually 10-12 mm). Specify 2 layers for two-layer reinforcement. The calculator will calculate the bars in both directions and the total amount of reinforcement.
The amount of reinforcement per cube of concrete depends on the type of structure: for foundations 50-150 kg/m³, for floor slabs 80-120 kg/m³, for walls 40-80 kg/m³, for columns 150-250 kg/m³. The exact quantity is calculated by the calculator based on the specific dimensions and grid spacing.
The number of rods is calculated by the formula: (Structure size / Grid pitch + 1) × Number of layers. For example, for a slab 6 m long with a pitch of 200 mm and 2 layers: (6/0.2 + 1) × 2 = 31 × 2 = 62 rods along the length. Then multiplied by the width for the total length.
For floor slabs, reinforcement with a diameter of 8-12 mm is usually used. For thin slabs (up to 15 cm) Ø8-10 mm is sufficient, for thick slabs (15-25 cm) Ø10-12 mm is used, for very thick slabs (more than 25 cm) Ø12-14 mm or more is used. The choice depends on the load on the floor.
The overlap of the reinforcement when connecting the rods should be at least 30-50 times the diameter of the reinforcement. For example, for reinforcement Ø12 mm the overlap is 360-600 mm. The overlap is taken into account when calculating the total length of the reinforcement - the overlap length is added to each length of the rod.
Yes, the calculator supports the calculation of reinforcement for columns. Enter the column section dimensions (length and width), height, stirrup spacing, longitudinal reinforcement diameter, and stirrup diameter. The calculator will calculate the number of longitudinal bars, the number of clamps and the total weight of the reinforcement.
For a monolithic wall, enter the length, width (thickness) and height of the wall, grid spacing (usually 200-300 mm) and reinforcement diameter (usually 8-10 mm). The calculator will calculate vertical and horizontal rods. For thin walls one layer is enough, for thick walls two layers are enough.
For a slab foundation, the amount of reinforcement depends on the area of the slab, grid spacing and diameter. For example, for a slab 8x8 m with a pitch of 200 mm and reinforcement Ø12 mm, about 650-750 kg of reinforcement will be required with two-layer reinforcement. The calculator will accurately calculate the required amount.
The reinforcement class is selected based on the load: A400 (old marking A-III) is suitable for most structures, A500 (modern marking) has higher strength and is recommended for critical structures. The calculator calculates the quantity regardless of the class, but the weight is the same for the same diameters.
The protective layer of concrete should be: for foundations in the ground - at least 4 cm, for foundations not in the ground - 3 cm, for walls and slabs up to 25 cm - 2 cm, for slabs and walls over 25 cm - 2.5 cm. The calculator does not take into account the protective layer in calculating the length, but it must be taken into account during installation.
Yes, reinforcing mesh can be used instead of individual bars. The mesh simplifies installation and ensures precise pitch. The calculator calculates the equivalent number of rods for a mesh with a given pitch. When using mesh, consider standard roll and sheet sizes.
The cost of fittings is calculated as the product of weight and price per kilogram. Enter the price of the reinforcement (usually 50-80 ₽/kg depending on the diameter and region), the calculator will show the total cost. For an accurate calculation, also take into account the cost of delivery and cutting of reinforcement.
For a strip foundation of a private house, the optimal reinforcement mesh pitch is 150-200 mm. For a slab foundation, the pitch is usually 200-250 mm. A smaller pitch (100-150 mm) is used for heavy loads or on soft soils. The calculator will help you choose the optimal step for your case.
For the grillage, enter the length, width and height, grid pitch (usually 150-200 mm) and reinforcement diameter (usually 12-14 mm). The grillage requires two layers of reinforcement, so specify 2 layers. The calculator will calculate the longitudinal and transverse rods for the upper and lower chords.
Yes, you can calculate the reinforcement for each element (foundation, walls, floors, columns) separately and summarize the results. The calculator saves results that can be exported to Excel to summarize and analyze the total reinforcement consumption for the entire project.
The number of stirrups for a column is calculated as (Column height / Stirrup spacing + 1). For example, for a column 3 m high with a stirrup pitch of 150 mm: (3/0.15 + 1) = 21 stirrups. The length of one clamp is calculated as the perimeter of the column, taking into account the protective layer.
The amount of reinforcement per m² of slab depends on the grid pitch and diameter. With a pitch of 200 mm and reinforcement Ø10 mm: about 5 m/m² or 3-3.5 kg/m² with two-layer reinforcement. With a step of 150 mm, the flow rate increases to 6-7 m/m² or 4-4.5 kg/m². The calculator will accurately calculate for your parameters.
For a ribbed floor, calculate the reinforcement for the slab separately, then for the ribs. The ribs use reinforcement of a larger diameter (12-16 mm) with a smaller pitch. The calculator allows you to calculate each item separately, then add the results to get the total quantity.
Weight of one meter of reinforcement according to GOST: Ø6 mm - 0.222 kg/m, Ø8 mm - 0.395 kg/m, Ø10 mm - 0.617 kg/m, Ø12 mm - 0.888 kg/m, Ø14 mm - 1.21 kg/m, Ø16 mm - 1.58 kg/m, Ø18 mm - 2.0 kg/m, Ø20 mm - 2.47 kg/m, Ø22 mm - 2.98 kg/m, Ø25 mm - 3.85 kg/m. The calculator uses these values automatically.
According to the standards, the minimum amount of reinforcement for the foundation must be at least 0.1% of the cross-sectional area for longitudinal reinforcement. For a strip foundation with a width of 400 mm and a height of 600 mm, the minimum reinforcement area is: 0.001 × 400 × 600 = 240 mm². This is approximately 4 rods Ø10 mm or 2 rods Ø12 mm per meter of length.
Yes, composite (fiberglass or basalt-plastic) reinforcement can be used instead of steel. It has less weight (3-4 times lighter) and is not subject to corrosion. When calculating, take other strengths and elasticities into account. The calculator calculates the number of rods the same, but the weight needs to be recalculated.
For a monolithic staircase, calculate the reinforcement for flights and landings separately. In flights, reinforcement Ø10-12 mm is used with a pitch of 150-200 mm, in platforms - similarly. The calculator allows you to calculate each element (length and width of the flight, dimensions of the landings) and obtain the total amount of reinforcement for the stairs.
For one pile with a diameter of 300 mm and a height of 2 m with reinforcement Ø12 mm, you will need 4-6 longitudinal rods 2 m long (8-12 m total) and clamps with a pitch of 150-200 mm (about 13-17 clamps). Total weight for one pile: about 15-25 kg. Multiply by the number of piles to obtain the total consumption.
For a floor beam, enter the length, width and height of the beam, the pitch of the transverse reinforcement (usually 150-200 mm) and the diameters of the longitudinal (12-16 mm) and transverse (6-8 mm) reinforcement. The calculator will calculate longitudinal rods for the lower and upper chords and transverse rods (clamps) for the entire beam.
When calculating, take into account reinforcement waste of 5-10% for scraps and non-standard lengths. The calculator shows the exact quantity required to which the stock needs to be added. The standard length of the reinforcement is 11.7-12 m; when calculating, take into account the optimization of the length of the rods to minimize waste.
For a foundation with a basement, calculate the reinforcement for the external and internal walls separately, then for the basement floor slab. Use the same reinforcement parameters (pitch, diameter) for all elements. The calculator allows you to calculate each element separately, then sum the results to obtain the total consumption.
In the corners of the foundation, additional reinforcement with reinforcement is required due to stress concentration. Use L-shaped or U-shaped elements made of reinforcement with a diameter equal to the main reinforcement, with a length of at least 40 diameters in each direction. 20-30% of additional reinforcement from the main one is added to the corner reinforcement.